Work done by the tension is ⁵/₄ MgL
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Further explanation
Let's recall the Kinetic Energy and Work formula as follows:
[tex]\boxed {E_k = \frac{1}{2}mv^2 }[/tex]
Ek = kinetic energy ( J )
m = mass of object ( kg )
v = speed of object ( m/s )
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[tex]\boxed {W = F d}[/tex]
W = work done ( J )
F = force ( N )
d = displacement ( m )
Let us now tackle the problem!
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Given:
acceleration of the object = a = g/4
initial speed of the object = u = 0 m/s
distance traveled = d = L
Asked:
work done by the tension = W = ?
Solution:
We will use Newton's Law of Motion to solve this problem:
[tex]\Sigma F = Ma[/tex]
[tex]T - w = Ma[/tex]
[tex]T = w + Ma[/tex]
[tex]T = Mg + M\frac{g}{4}[/tex]
[tex]T = \frac{5}{4}Mg[/tex]
[tex]T L = \frac{5}{4} MgL[/tex]
[tex]W = \frac{5}{4} MgL[/tex]
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Conclusion :
Work done by the tension is ⁵/₄ MgL
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Learn more
- Velocity of Runner : https://brainly.com/question/3813437
- Kinetic Energy : https://brainly.com/question/692781
- Acceleration : https://brainly.com/question/2283922
- The Speed of Car : https://brainly.com/question/568302
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Answer details
Grade: High School
Subject: Mathematics
Chapter: Energy
