contestada

You shake a bottle of soda and take off the cap. If the soda shoots out of the
bottle with a velocity of 15 m/s, how high will it go?
A. 11.5 m
B. 8.3 m
C. 10.6 m
D. 12.7 m

Respuesta :

Answer:

A. 11.5 m

Explanation:

Given,

The initial velocity of the soda cap, u = 15 m/s

The soda bottle cap is projected vertically upwards,

Hence, the angle formed with the ground, Ф = 90°

The maximum height of the projectile is given by the formula,

                                    [tex]h_{max} =\frac{u^{2}sin^{2}\phi}{2g}[/tex]

Substituting the given values in the above equation

                                   [tex]h_{max} =\frac{15^{2}sin^{2}90}{2X9.8}[/tex]

                                                        = 11.5 m

Hence, the maximum height of the cap is h = 11.5 m