Answer:
[tex]6.6*10^{27}e/m^3[/tex]
Explanation:
When we are dealing with Hall voltage, it is necessary to have the values of the current, the magnetic field, the length, the area and the number of carriers at hand. The Hall voltage equation is given by,[tex]V_h = \frac{iB}{neL}[/tex]
Where,
i= current
B= Magnetic field
L = Length
n = number of charge carriers
e= charge of a electron
We need replace and solve for n,
[tex]n= \frac{iB}{V_h e L}[/tex]
[tex]n= \frac{2*1.2}{4.5*10^{-6}*5^10^{-3}*1.6*10^{-19}}[/tex]
[tex]n= 6.6*10^{27}electron.m^{-3}[/tex]
Therefore the density of charge carrier is [tex]6.6*10^{27}e/m^3[/tex]
