Respuesta :
Answer:
a) 36 m
b) 64 m
Explanation:
Given:
v₀ = 0 m/2
v = 12 m/s
t = 6 s
Find: Δx
Δx = ½ (v + v₀) t
Δx = ½ (12 m/s + 0 m/s) (6 s)
Δx = 36 m
The track is 100 m, so the sprinter still has to run another 64 m.
If a sprinter accelerates from rest to a velocity of 12m/s in the first 6 seconds of the 100-meter dash, then the sprinter travels 72 m during the first 6 seconds and the sprinter has to travel 28 m more to reach the finish line
What are the three equations of motion?
There are three equations of motion given by Newton
The first equation is given as follows
v = u + at
the second equation is given as follows
S = ut + 1/2×a×t²
the third equation is given as follows
v² - u² = 2×a×s
Keep in mind that these calculations only apply to uniform acceleration.
As given in the problem,a sprinter accelerates from rest to a velocity of 12m/s in the first 6 seconds of the 100-meter dash
By using the first equation of the motion
v = u + at
12 = 0+a*6
a = 2 m/s²
initial velocity(u) = 0 m/s
acceleration(a) = 9.81 m/s²
By using the second equation of motion
S = ut + 1/2at²
,u= 0 m/s , a= 2m/s² and t =6 seconds
S = 0 +2×6²
S =72 meter
As he has to cover a total of 100 meters, the sprinter has to travel 28 m more to reach the finish line
Thus, the sprinter travels 72 m during the first 6 seconds and the sprinter has to travel 28 m more to reach the finish line
Learn more about equations of motion from here
brainly.com/question/5955789
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