The force that represents the weight in the free-body diagram is the arrow pointing downward (labelled with W).
Explanation:
The free-body diagram (FBD) is missing, so I have attached it to the answer.
The FBD shows all the forces acting on the car. There are essentially 4 forces in this situation:
1) The thrust (T) --> it is the force provided by the car's engine. It acts forward.
2) The air resistance (R) --> it is the force due to the presence of the air, that opposes the motion of the car. This force acts backward, because it always acts in the direction opposite to the motion.
3) The weight of the car (W) --> it is the force due to gravity (it is the gravitational attraction exerted by the Earth on the car). It always acts downward, and its magnitude can be calculated as
W = mg
where m is the mass of the car and g is the acceleration due to gravity.
4) The normal reaction of the road on the car (N) --> it is the reaction force exerted by the road on the car, and it acts upward, balancing the weight of the car and keeping it in equilibrium along the vertical direction.
So, the force that represents the weight in the free-body diagram is the arrow pointing downward (labelled with W).
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