The final equation of line passing through (6,9) and (11,2)
[tex]y=-\frac{7}{5}x+\frac{87}{5}[/tex]
Further explanation:
The general form of equation is:
[tex]y=mx+b[/tex]
We have to find the slope first
[tex]m=\frac{y_2-y_1}{x_2-x_1}\\Here\\(x_1,y_1)=(6,9)\\(x_2,y_2)=(11,2)\\Putting\ the\ values\\m=\frac{2-9}{11-6}\\=-\frac{7}{5}[/tex]
Putting the value of m in general form
[tex]y=-\frac{7}{5}x+b[/tex]
For finding the value of b, putting (6,9) in equation
[tex]9=-\frac{7}{5}(6)+b\\9=-\frac{42}{5}+b\\9+\frac{42}{5}=b\\b=\frac{45+42}{5}\\[/tex]
[tex]b=\frac{87}{5}[/tex]
Putting the values of b and m
The final equation of line passing through (6,9) and (11,2)
[tex]y=-\frac{7}{5}x+\frac{87}{5}[/tex]
Keywords: Equation of line, Slope
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