A person is standing on a spring bathroom scale on the floor of an elevator which is moving up and slowing down at the rate of 2.1 m/s 2 . The acceleration of gravity is 9.8 m/s 2 . If the person’s mass is 77.6 kg, what does the scale read? Answer in units of n

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usmanbiu usmanbiu · Answer 1 · 2019-11-09T19:57:01+01:00

Answer:

923.4 N

Explanation:

from the question we are given the following:

upward acceleration (a) = [tex]2.1 \frac{m}{s^{2} }[/tex]

downward acceleration (acceleration due to gravity (g)) = [tex]9.8 \frac{m}{s^{2} }[/tex]

mass (m) = 77.6 kg

the net acceleration is going to be the resultant of the upward and downward acceleration.

For the accelerations, let upward be positive and downward be negative

Therefore

net acceleration = g - (-a) (note that the negative sign in front of "a" (-a) is because the person was decelerating)

= 9.8 - (-2.1) = 11.9

now we can get the reading on the scale from F = m x a

F = 77.6 x 11.9 = 923.4 N

andromache andromache · Answer 2 · 2022-02-08T15:14:47+01:00

The scale read is 923.4 N

Here the net acceleration should be of the upward and downward acceleration.

For the accelerations, here we assume the upward be positive and downward be negative

So,

net acceleration = g - (-a)

= 9.8 - (-2.1)

= 11.9

Now reading on the scale from [tex]F = m \times a[/tex]

[tex]F = 77.6 \times 11.9[/tex]

= 923.4 N

Find out more information about the mass here : brainly.com/question/15959704?referrer=searchResults