Answer:
5 & 1
Step-by-step explanation:
We can use the quadratic formula to solve this:
Quadratic Formula = [tex]\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]
So we will have 2 answers (roots).
a is the coefficient of x^2 (2)
b is the coefficient of x (-12)
c is the constant (10)
Now, substituting, we get:
x = [tex]\frac{-b+-\sqrt{b^2-4ac} }{2a}=\frac{12+-\sqrt{(-12)^2-4(2)(10)} }{2(2)}=\frac{12+-\sqrt{64} }{4}=\frac{12+-8}{4}=\frac{12+-8}{4}=5,1[/tex]
Hence the roots are 5 & 1
