I attached a diagram, according to the description given, to better understand the problem. The car accelerates, at a 'a' speed, which will also experience the hanging object, in two components:
The one in x, with 'a' in the opposite direction to the car's address
The one found in y, the product of gravity. The two components are related through the tangent and the respective angle, as well,
[tex]tan\theta = \frac{ma}{mg}[/tex]
[tex]tan\theta = \frac{a}{g}[/tex]
To identify, we know that it can be expressed as a function of speed,
[tex]a= \frac{\Delta v}{t} = \frac{v-u_0}{5.1}\frac{26.8}{5.1}[/tex]
[tex]a=5.26m/s^2[/tex]
Replacing in our angle formula,
[tex]tan\theta = \frac{5.26}{9.8}[/tex]
[tex]tan\theta = 0.54[/tex]
[tex]\theta = tan^{-1}(0.54)[/tex]
[tex]\theta = 28.4\°[/tex]
If there is no friction, we consider the vertical forces of both the Washes and the Normal car. So,
[tex]F=ma[/tex]
Therefore the relationship with the vertical component would be given by,
[tex]\Rightarrow \frac{F}{mg} = \frac{ma}{mg} = \frac{a}{g}=\frac{5.26}{9.8}=0.54 =54\%[/tex]
A) The size of the angle that the string makes with the line you draw when the car accelerates at the claimed rate is : 28.4°
B) The ratio of the frictional force to the gravitational force exerted on this washer is : 0.54
Given that :
velocity ( v )= 26.8 m/s
time = 5.1 secs
Size of angle is determined by
Tan ∅ = ma / mg
Tan ∅ = a / g ----- ( 1 )
where ; a = Δv / t = 26.8 / 5.1
= 5.26 m/s²
Back to equation ( 1 )
Tan ∅ = 5.26 / 9.8
= 0.54
∅ = tan⁻¹ ( 0.54 ) = 28.4°
B) The ratio of the frictional force to gravitational force when an identical washer does not slide on the horizontal dashboard can be calculated using the equation below
F / mg = ma / mg. ---- ( 2 )
Given that there is no friction
Equation ( 2 ) becomes
a / g = 5.26 / 9.8
= 0.54
Hence we can conclude that the answers to your questions as as listed above.
Learn more about Gravitational force : https://brainly.com/question/862529
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