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Assume Earth being a uniform sphere with mass M ≈ 6×10^24 kg and radius R ≈ 6400 km. Suppose that you could harness the Earth’s kinetic energy of rotation. If mankind requires a total power of P = 10^14 W, how long could you supply this amount of power by spinning down the Earth?

Respuesta :

Answer:

5.16×10¹⁵ s

Explanation:

Considering the rotational motion of the Earth,

K.E. = [tex]\frac{1}{2}I[/tex]ω²    where, I = [tex]\frac{2}{5}[/tex]MR²

      = [tex]\frac{2}{5}[/tex]MR²ω²  ---------(1)   where ω = angular velocity of Earth

To find ω,

ω = 2π/T           where T =  time period of Earth

    = 2π/(60×60×24) = 7.27×10^-5 rad/s

Substituting the values in (1),

K.E. = 0.4×(6×10^24)×(6400000)²×(7.27×10^-5)²

       = 5.16×10²⁹ J

To calculate possible time,

Time = Energy/ Power

        = 5.16×10²⁹ / 10¹⁴

        = 5.16×10¹⁵ s