Answer:
[tex]m=\frac{1}{2}[/tex]
Step-by-step explanation:
Actually the function that has this points (2,3) and (4,2) is not y=x+1 when we plug those values it is not true for (4,2).
Then algebraically calculating we have
1)[tex]y=\frac{1}{2}x+4[/tex]
[tex](2,3) , (4,2) \in \:y-3=(x-2)[/tex]
[tex]m=\frac{y-y_0}{x-x_0}\Rightarrow m=\frac{2-3}{4-2}\Rightarrow m=\frac{-1}{-2} m=\:m=\frac{1}{2}[/tex]
The slope equals [tex]m=\frac{1}{2}[/tex]
