Answer:
Part b
[tex]B = 8\frac{\mu_o I}{5\sqrt5 R}[/tex]
Explanation:
Part a)
Let the radius of the coil is R and magnetic field on its axis is given as
[tex]B = \frac{\mu_o I R^2}{2(z^2 + R^2)^{3/2}}[/tex]
now we know that two coils are identical and we need to find magnetic field between two coils
so we will have net magnetic field given as
[tex]B = \frac{\mu_o I R^2}{2(z^2 + R^2)^{3/2}} + \frac{\mu_o I R^2}{2((d-z)^2 + R^2)^{3/2}}[/tex]
Now we know that magnetic field is maximum at position
[tex]\frac{dB}{dz} = 0[/tex]
so we will have
[tex]z - (d - z) = 0[/tex]
[tex]z = \frac{d}{2}[/tex]
so it will be at mid point of two coils
Part b)
Now we know that
[tex]\frac{d^2B}{dz^2} = 0[/tex]
so we will have
[tex]d = R[/tex]
now magnetic field is given as
[tex]B = 2\frac{\mu_o I R^2}{2(z^2 + R^2)^{3/2}}[/tex]
put z = 0.5 R
[tex]B = 8\frac{\mu_o I}{5\sqrt5 R}[/tex]