Which equation can be solved using the expression StartFraction negative 3 plus-or-minus StartRoot (3) squared + 4 (10) (2) EndRoot Over 2 (10) EndFraction for x?
10x2 = 3x + 2
2 = 3x + 10x2
3x = 10x2 – 2
10x2 + 2 = –3x

Respuesta :

Answer: B.  2 = 3x + 10x2

Step-by-step explanation:

This is the concept of quadratic equations; We required to find the type of equation that can be solved using the model that has been used to solve the equation such that the answer is:

[-3+-sqrt(3^2+4(10)(2))]/(2(10))

The formual that was applied here was a quadratic formula given by:

x=[-b+\-sqrt(b^2-4ac)]/2a

whereby from the our substituted values above,

a=10,b=3 and c=-2

such that the quadratic equation will be:

10x^2+3x-2 

Equation can be solved using the expression  2 = 3x + 10x2

This is the concept of quadratic equations; We are required to find the type of equation that can be solved using the model that has been used to solve the equation such that the answer is:

[tex][-3+-sqrt(3^2+4(10)(2))]/(2(10))[/tex]

The formula that was applied here was a quadratic formula given by:

[tex]x=[-b+\-√(b^2-4ac)]/2a[/tex]

whereby from our substituted values above,

a=10,b=3 and c=-2

such that the quadratic equation will be:

[tex]10x^2+3x-2[/tex]

What is Quadratic equations?

Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax2 + bx + c = 0 where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where 'a' is called the leading coefficient and 'c' is called the absolute term of f (x).

Formula

[tex]ax^2+bx+c=0[/tex]

To learn more about Quadratic equations refer to:

https://brainly.com/question/1214333

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