An ice skater starts with a velocity of 2.25 m/s in a 50.0 degree direction. After 8.33s, she is moving 4.65 m/s in a 120 degree direction. What is the x-component of her acceleration?

Respuesta :

The x-component of the acceleration is [tex]-0.45 m/s^2[/tex]

Explanation:

In order to find the x-component of the acceleration, we just need to analyze the motion in the x-direction.

The acceleration along the x-direction is given by:

[tex]a_x = \frac{v_x-u_x}{t}[/tex]

where

[tex]v_x[/tex] is the final velocity in the x-direction

[tex]u_x[/tex] is the initial velocity in the x-direction

t is the time

At the beginning, the ice skater is moving at

u = 2.25 m/s

in a direction

[tex]\theta=50.0^{\circ}[/tex]

So the initial velocity in the x-direction is

[tex]u_x = u cos \theta = (2.25)(cos 50.0)=1.45 m/s[/tex]

After t = 8.33 s, the ice skater is moving at

v = 4.65 m/s

in a direction

[tex]\theta=120^{\circ}[/tex]

So the final velocity in the x-direction is

[tex]v_x = vcos \theta=(4.65)(cos 120)=-2.33 m/s[/tex]

Therefore, the x-component of the acceleration is:

[tex]a_x = \frac{-2.33 - 1.45}{8.33}=-0.45 m/s^2[/tex]

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