Please help ASAP!!!

The price of the radio changes from $40.00 to $44.00.

A. 10% decrease

B. 10% increase ***

C. 36.4% decrease

D. 40% increase


The price of an oven changes from 450 to 396

A. 13.6%increase

B. 13.6% decrease

C. 12% increase

D. 12% decrease ***


The top players average changes from 20 points per game to 24 points per game

A. 20% increase ***

B. 20%decrease

C.16.7% increase

D. 4% decrease


At the start of the football season, Jorge weighed 150 pounds. At the end of the season, he weighed 138 pounds. What was the percent change in his weight?

A. 8% increase

B.12% increase

C. 8.7% decrease

D. 8% decrease ***


Sara raised her score on the math test from 86 to 94. Max changes his score on the test from 77 to 85. Who had the greater percent change?

A. They both had the same percent change. ***

B. Max’s percent was about 1.1% more than Sara’s.

C. Sara’s percent increase was about 10% more than Max’s

D. Max’s percent increase was about 105 more than Sara’s

Please chack my answers

***= My answer

Respuesta :

Answer:

1)b

2)d

3)a

4)d

5)a

your answers are correct

Step-by-step explanation:

The percentage changes of the following situations are required.

The answers are

B. 10% increase

D. 12% decrease

A. 20% increase

D. 8% decrease

B. Max’s percent was about 1.1% more than Sara’s.

The formula for percentage change is

[tex]\dfrac{\text{Final}-\text{Initial}}{\text{Initial}}\times 100[/tex]

If the sign of the change is negative it is a decrease.

If the sign of the change is positive it is an increase.

Final value = $44

Initial value = $40

The percentage change is

[tex]\dfrac{44-40}{40}\times 100=10\%[/tex]

Final value = 396

Initial value = 450

The percentage change is

[tex]\dfrac{396-450}{450}\times 100=-12\%[/tex]

Final value = 24

Initial value = 20

The percentage change is

[tex]\dfrac{24-20}{20}\times 100=20\%[/tex]

Final value = 138

Initial value = 150

The percentage change is

[tex]\dfrac{138-150}{150}\times 100=-8\%[/tex]

Sara

Final value = 94

Initial value = 86

The percentage change is

[tex]\dfrac{94-86}{86}\times 100=9.3\%[/tex]

Max

Final value = 85

Initial value = 77

The percentage change is

[tex]\dfrac{85-77}{77}\times 100=10.4\%[/tex]

Difference = [tex]10.4-9.3=1.1\%[/tex]

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