(1) 27 ⁷/₉ seconds
(2) 8: 07 : 15 AM
Step-by-step explanation:
(1)
If the trains travel 18 m in every second. How many seconds would have it cover 500m
18m : 1s
500m : ? (x) s
We cross multiply;
18 * x = 500 * 1
500/18 = x
X = 27 ⁷/₉ seconds
(2)
How long would the same train cover the 40 km journey
40km = 40 * 1000m = 40000
18m : 1 s
40000m : ? (x) s
Cross-multiply;
40000 * 1 = 18 * x
40000/18 = x
X = 2,222 2/9 seconds
2,222 / 60
37 minutes ²/₆₀ seconds
Lets add the fraction seconds;
²/₆₀ + ²/₉ = ¼ second
= 37 minutes & ¼ seconds
Lets add this to the departure time of 7: 30 AM
7: 30: 00 + 0 : 37: 15
= 8: 07 : 15 AM
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