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Joe pushes down the length of the handle of an 11.6 kg lawn spreader. The handle makes an angle of 46.2 ◦ with the horizontal. Joe wishes to accelerate the spreader from rest to 1.37 m/s in 1.6 s. What force must Joe apply to the handle? Answer in units of N.

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Answer:

F = 9.93N

Explanation:

We start the development of the exercise through the second law of Newton.

The second law tells us that

[tex]F = m a[/tex]

But we also understand that Acceleration is the change in speed in a given time, this is

[tex]a = \frac {\Delta V} {\Delta t}[/tex]

Replacing,

[tex]F = m \frac {\Delta V} {\Delta t}[/tex]

Our values are,

[tex]m = 11.6Kg\\\Delta V = 1.37m / s\\\Delta t = 1.6s[/tex]

Substituting

[tex]F = 11.6 * \frac {1.37} {1.6}[/tex]

[tex]F = 9.93N[/tex]

We can conclude that the force Joe must apply in the handle is 9.93N

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