For this case we have that by definition, the equation of a line of the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have to, if two lines are parallel then their slopes are equal.
We have the following equation of the line:
[tex]2x + 4y = 5[/tex]
We manipulate algebraically to convert to the slope-intersection form:
[tex]4y = -2x + 5\\y = - \frac {2} {4} x + \frac {5} {4}\\y = - \frac {1} {2} x + \frac {5} {4}[/tex]
Thus, [tex]m_ {1} = - \frac {1} {2}[/tex], then a parallel line will have a slope [tex]m_ {2} = - \frac {1} {2}.[/tex]
Answer:
The slope is: [tex]m_ {2} = - \frac {1} {2}[/tex]
