Answer:
33.2 cm³
Explanation:
We are given;
Density of Aluminium is 2.70 g/cm³
Number of atoms of Aluminium is 2.00 × 10^24 atoms
We are required to calculate the volume of the cube;
We know that 1 mole of a compound or an element contains a number of particles equivalent to the Avogadro's constant.
Therefore;
1 mole of Aluminium contains 6.022 × 10^23 atoms
But, 1 mole of Al = 27 g
Therefore;
27 g of Al contains 6.022 × 10^23 atoms
We need to calculate the mass that contains 2.00 × 10^24 atoms
Moles of Al = (2.00 × 10^24 atoms) ÷ (6.022 × 10^23 atoms)
= 3.32 moles
Mass of Al = 27 g/mol × 3.32 moles
= 89.64 g
We can then calculate volume of Aluminium
Density = Mass ÷ Volume
Rearranging the formula;
Volume = Mass ÷ Density
= 89.64 g ÷ 2.70 g/cm³
= 33.2 cm³
