An I/O-bound program is one that, if run alone, would spend more time waiting for I/O than using the processor. A processor-bound program is the opposite. Suppose a short-term scheduling algorithm favors those programs that have used little processor time in the recent past. Explain why this algorithm favors I/O-bound programs and yet does not permanently deny processor time to processor-bound programs.

Question

08-11-2019
Computers and Technology

contestada

An I/O-bound program is one that, if run alone, would spend more time waiting for I/O than using the processor. A processor-bound program is the opposite. Suppose a short-term scheduling algorithm favors those programs that have used little processor time in the recent past. Explain why this algorithm favors I/O-bound programs and yet does not permanently deny processor time to processor-bound programs.

Respuesta :

Otras preguntas

Which of the following is equivalent to 24:72? a. 1:3 b. 2:4 c. 2:3 d. 3:1

The graph of a system of two linear equations is a pair of lines that intersect at the origin. Which statement is true of the system?

. Carlee surveyed customers as they left a convenience store. She asked them, “How many items did you purchase?” The results are shown in the line plot. (a) How

Help me please I do not understand this assignment

need help with this math hw

How do public officials use opinion polls? A. To determine which candidates won in recent state or federal elections B. To gauge the public’s level of support

Which universal theme is BEST reflected in this passage? es ) A) The quest for romantic love long B) The desire for self knowledge The return of a great warrior

PLS HURRY GIVING BRAINLIEST(05.03)Bev has to cut her grandma's grass this weekend and wants to know exactly how much area she will be cutting. Calculate the are

According to the Rational Root Theorem, the following are potential roots of f(x) = 2x2 + 2x – 24. –4, –3, 2, 3, 4 Which are actual roots of f(x)

can someone please help me solve this? thank you!

Limosa Limosa · Answer 1 · 2019-11-11T13:20:45+01:00

Answer with Explanation:

An I/O-bound the programs that are used relatively a little processor times and are favored by an algorithm. However, if the processor bound process is denied the processor time for the sufficiently long periods of times, the same algorithms will be granted a processor to the process and it has not use the processors at all in recent pasts. Therefore, the processor bound process will not be the permanently denied to access.