Respuesta :
Answer:
On a coordinate plane, a cube root function goes through (negative 8, negative 2), has an inflection point at (0, 0), and goes thorugh (8, 2).
Step-by-step explanation:
[tex]f(x)=\sqrt[3]{x}\\\\f(-8)=\sqrt[3]{-8}=-2\to(-8,\ -2)\\\\f(0)=\sqrt[3]{0}=0\to(0,\ 0)\\\\f(8)=\sqrt[3]{8}=2\to(8,\ 2)\\\\\\\sqrt[3]{a}=b\iff b^3=a\\\\\text{Therefore:}\\\\\sqrt[3]{-8}=-2\ \text{because}\ (-2)^3=-8\\\sqrt[3]0=0\ \text{because}\ 0^3=0\\\sqrt[3]{8}=2\ \text{because}\ 2^3=8[/tex]
