Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the following reaction equation. 2H202(aq) →2H20(/) + 02(g) The activation energy for this reaction is 75 kJ/mol. In the presence of a metal catalyst the activation energy is lowered to 49 kJ/mol. At what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the metal-catalyzed reaction at 25°C?

Respuesta :

Answer : The temperature for non-catalyzed reaction needed will be 456 K

Explanation :

Activation energy : The energy required to initiate the reaction is known as activation energy.

According to the Arrhenius equation,

[tex]K=A\times e^{\frac{-Ea}{RT}}[/tex]

Since, the rate for both the reaction are equal.

[tex]K_1=K_2[/tex]

[tex]A\times e^{\frac{-Ea_1}{RT_1}}=A\times e^{\frac{-Ea_2}{RT_2}}[/tex]

[tex]\frac{Ea_1}{T_1}=\frac{Ea_2}{T_2}[/tex] ..........(1)

where,

[tex]Ea_1[/tex] = activation energy for non-catalyzed reaction = 75 kJ/mol

[tex]Ea_2[/tex] = activation energy for catalyzed reaction = 49 kJ/mol

[tex]T_1[/tex] =  temperature for non-catalyzed reaction = ?

[tex]T_2[/tex] = temperature for catalyzed reaction = [tex]25^oC=273+25=298K[/tex]

Now put all the given values in the above formula 1, we get:

[tex]\frac{Ea_1}{T_1}=\frac{Ea_2}{T_2}[/tex]

[tex]\frac{75kJ/mol}{T_1}=\frac{49kJ/mol}{298K}[/tex]

[tex]T_1=456K[/tex]

Therefore, the temperature for non-catalyzed reaction needed will be 456 K