Answer:
12739.74 N
Explanation:
m = Mass of load + Mass of elevator = 1200 kg
s = Displacement of the elevator = 62 m
g = Acceleration due to gravity = 9.81 m/s²
u = Initial velocity = 10 m/s
v = Final velocity = 0
Equation of motion
[tex]v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-10^2}{2\times 62}\\\Rightarrow a=-0.80645\ m/s^2[/tex]
Tension on the cable
[tex]T=m(g-a)\\\Rightarrow T=1200(9.81-(-0.80645))\\\Rightarrow T=12739.74\ N[/tex]
Here, as the elevator is going down the acceleration due to gravity and the acceleration will be subtracted.
Hence, the tension in the supporting cable is 12739.74 N
