Answer:
17.47%
Explanation:
We can solve this problem through change in the Kinetic Energy,
Our Kinetic Energy at the beggining is,
[tex]KE_i = \frac{1}{2} mv^2[/tex]
After applying a force, the increase is given by
[tex]KE_f = \frac{1+0.479}{2}mv^2[/tex]
[tex]KE_f = \frac{1.479}{2} mv^2[/tex]
The change in the kinetic energy is given by
[tex]\Delta KE = \frac{0.479}{2} mv^2[/tex]
In this way, we know that the displacement of sled is,
[tex]Fx = \frac{0.479}{2} mv^2[/tex]
When there is a positiving force of 68.6° we have in our Kinetic energy,
[tex]KE' = F*x cos68.6[/tex]
Substituting,
[tex]KE' = \frac{0.479}{2} mv^2 *cos 68.6[/tex]
[tex]KE ' = \frac{0.1747}{2} mv^2[/tex]
We can know define the % increased
[tex]\% Increased = \frac{KE'}{KE_i} = (\frac{\frac{0.1747}{2} mv^2 }{\frac{1}{2} mv^2})*100[/tex]
[tex]\% Increased = 17.47\%[/tex]
