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The Raptors are playing a best of 7 final series against the Golden State Warriors, where a team must win 4 games to win the series. Suppose the probability of the Raptors winning a game is 2/3 and the probability of the Golden State Warriors winning a game is 1/3. Suppose the Raptors won the first game; what is the probability the Golden State Warriors get their 4th win on the 7th game of the series?

Respuesta :

komalbasit2018

Answer:

Step-by-step explanation:

From the above situation we concluded that in 6 games there are equal wins for both teams. That means the score is 3-3. To compute the probability for win of Golden Star Warriors we use the formula

P = C(6,3)x(1/3)^7

P = 20x0.00046

P = 0.0092

We will have 6 choose 3 multiply by (1/3)^7 for the probability win of 4th game for golden star warriors.

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