Answer:
8 m/s
Explanation:
From the third law of motion
[tex]v^{2}=u^{2}+2as[/tex] where v is final velocity, u is initial velocity, a is acceleration, s is distance covered.
Since the bee takes off from rest, initial velocity is zero.
Substituting 0 for u, the equation becomes
[tex]v^{2}=0+2as=2as[/tex] and making v the subject of the formula
[tex]v=\sqrt {2as}[/tex]
Substituting 2 for a and 16 m for s
[tex]v=\sqrt {2*2*16}[/tex]
v=8 m/s
