Respuesta :
Answer:
The balloon filled with Helium will effuse more quickly.
Explanation:
Step 1: Data given
Balloon 1: Has a volume 4.3L , a pressure of 1.68 atm and is filled with 1.21g of Helium
Balloon 2: Has also a volume of 4.3 L and a pressure of 1.68 atm but is filled with 39.63 grams of Xenon
Molar mass of He = 4g/mol
Molar mass of Xe = 131.3 g/mol
Since He is lighter than Xe, the effusion rate for He will be larger than that for Xe, which means the time of effusion for He will be smaller than that for Xe.
The balloon filled with Helium will effuse more quickly.
Explanation:
It is known that according to Graham's law of effusion of gases.
[tex]\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}[/tex]
where, [tex]R_{1}[/tex] = rate of effusion of gas 1 = rate of effusion of He
[tex]R_{2}[/tex] = rate of effusion of gas 2 = rate of effusion of Xe
[tex]M_{1}[/tex] = molar mass of gas 1 = molar mass He = 4.0026 g/mol
[tex]M_{2}[/tex] = molar mass of gas 2 = molar mass Xe = 131.29 g/mol
Now, we will substitute the values into the above formula as follows.
[tex]\frac{R_{He}}{R_{Xe}} = \sqrt{\frac{M_{Xe}}{M_{He}}[/tex]
= [tex]\sqrt{\frac{131.29 g/mol}{4.0026 g/mol}}[/tex]
= [tex]\sqrt{32.8}[/tex]
= 5.73
Thus, we can conclude that helium effuses 5.73 times faster than Xenon.
