Because of interstellar dust, astronomers can see at most about 5 kpc into the disk of the galaxy at visual wavelengths. What percentage of the galactic disk does that include? (Hint: Consider the area of the entire disk versus the area visible from Earth. The diameter of the Milky Way Galaxy is approximately 25 kpc.)

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horaciocrotte horaciocrotte · Answer 1 · 2019-11-09T20:29:02+01:00

Answer:

96%

Explanation

Let A the total area of the galaxy, is modeled as a disc:

A = πR^2 = π (25 kpc)^2

And let a be the area that astronomers are able to see:

a = πr^2 = π(5 kpc)^2

The percentage that can be seen is equal to 100 times the ratio of the areas, of the galaxy and the "visible" part:

P = 100 a/A = (5/25)^2 = 100/25 = 4%

Therefore, the percentage of the galaxy not included, i.e. not seen is:

(100-4)% = 96%

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adefioyelaoye adefioyelaoye · Answer 2 · 2022-03-24T14:19:39+01:00

The percentage of the galactic disk is 96%.

This is defined as a number which is expressed as a fraction of 100.

Area = πR²

Total area of galaxy = π (25 kpc)²

Area that astronomers can see:

a = πr² = π(5 kpc)²

Percentage = 100X the ratio of the areas, of the galaxy and the "visible" part

P = 100 a/A = (5/25)² = 100/25 = 4%

Percentage of the galaxy not seen is (100-4)% = 96%

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