Answer:
[tex]N\approx50929580[/tex]
Explanation:
Given:
factor of increase of blood flow, f = 4
cross-sectional area of venules, [tex]a=10\,cm^2[/tex]
diameter of the capillaries involved in venule formation, [tex]d=10\times 10^{-3}\,cm[/tex]
Now, area of each capillary:
[tex]a_c=\pi \frac{(10\times 10^{-3})^2}{4}[/tex]
[tex]a_c=7.854\times 10^{-7}\,cm^2[/tex]
No. of capillaries that will combine to form the venule of given cross-section area:
[tex]N=\frac{a}{a_c}[/tex]
[tex]N=\frac{10}{7.854\times 10^{-7}}[/tex]
[tex]N\approx50929580[/tex]
