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On a highly polished, essentially frictionless lunch counter, a 0.530 kg submarine sandwich moving 3.25 m/s to the left collides with a 0.260 kg grilled cheese sandwich moving 1.25 m/s to the right. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Inelastic collision on an air track. Part A If the two sandwiches stick together, what is their final velocity? Express your answer with the appropriate units. Enter positive value if the direction of the velocity is to the right and negative value if the direction of the velocity is to the left.

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opudodennis

Answer:

1.77 m/s

Explanation:

From the law of conservation of linear momentum, the initial momentum equals the final momentum. Generally, momentum is given by mv where m is mass and v is velocity.

Taking right to be positive and left negative

[tex](0.53 Kg*-3.25 m/s)+(0.26 Kg*1.25 m/s)=(0.53 Kg+0.26 Kg)v_c[/tex]

[tex]-1.3975=0.79v_c[/tex]

[tex]vc=\frac {-1.3975}{0.79}=-1.768987342\approx -1.77 m/s[/tex]

Therefore, they move towards left at a speed of 1.77 m/s

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