Answer:
0.4082
Step-by-step explanation:
Given that the number of customers received by a drive-through pharmacy on Saturday mornings between 8:00 AM and 9:00 AM has a Poisson distribution with λ (Lambda) equal to 1.4.
X has Poisson mean=1.4
the probability of getting at least 2 customers between 8:00 am and 9:00 am in the morning
=[tex]P(X\geq 2)\\=0.4082[/tex]
Required probability = 0.4082
