Ammonia is produced commercially by the direct reaction of the elements. The formation of 1.00 moles of gaseous NH3 by this reaction releases 46.17 kJ of heat. How much energy (in kJ) is released, when 28.0 kg of hydrogen gas, H2, reacts in excess nitrogen gas, N2?

Respuesta :

Answer:

[tex]4.28\times 10^{5}kJ[/tex] of heat energy will be released

Explanation:

Balanced reaction-

[tex]\frac{3}{2}H_{2}+\frac{1}{2}N_{2}\rightarrow NH_{3}[/tex]

According to balanced equation, [tex]\frac{3}{2}[/tex] moles of [tex]H_{2}[/tex] produces 1 mol of [tex]NH_{3}[/tex] to release 46.17 kJ of heat.

Molar mass of [tex]H_{2}[/tex] = 2.016 g/mol

Number of moles = (mass)/(molar mass)

So, 28 kg of [tex]H_{2}[/tex] = 28000 g of [tex]H_{2}[/tex]

                                              = [tex]\frac{28000}{2.016}[/tex] moles of [tex]H_{2}[/tex]

                                               = [tex]1.389\times 10^{4}[/tex] moles of [tex]H_{2}[/tex]

So. [tex]1.389\times 10^{4}[/tex] moles of [tex]H_{2}[/tex] react to release [tex](\frac{2}{3})\times (46.17)\times (1.389\times 10^{4})kJ[/tex] heat or [tex]4.28\times 10^{5}kJ[/tex] of heat