Answer:
[tex]4.28\times 10^{5}kJ[/tex] of heat energy will be released
Explanation:
Balanced reaction-
[tex]\frac{3}{2}H_{2}+\frac{1}{2}N_{2}\rightarrow NH_{3}[/tex]
According to balanced equation, [tex]\frac{3}{2}[/tex] moles of [tex]H_{2}[/tex] produces 1 mol of [tex]NH_{3}[/tex] to release 46.17 kJ of heat.
Molar mass of [tex]H_{2}[/tex] = 2.016 g/mol
Number of moles = (mass)/(molar mass)
So, 28 kg of [tex]H_{2}[/tex] = 28000 g of [tex]H_{2}[/tex]
= [tex]\frac{28000}{2.016}[/tex] moles of [tex]H_{2}[/tex]
= [tex]1.389\times 10^{4}[/tex] moles of [tex]H_{2}[/tex]
So. [tex]1.389\times 10^{4}[/tex] moles of [tex]H_{2}[/tex] react to release [tex](\frac{2}{3})\times (46.17)\times (1.389\times 10^{4})kJ[/tex] heat or [tex]4.28\times 10^{5}kJ[/tex] of heat