Answer:
The length of the actual submarine is 18 m.
Step-by-step explanation:
Here, the conversion ratio is
0.5 cm represents 3 m on actual submarine.
also, 3 m = 3 x 100 cm = 300 cm
or, the ratio of Drawing : Actual = 0.5 : 300
Now, Here drawing = 3 cm
let the actual length of the submarine = k cm
By the RATIO of PROPORTIONALITY:
[tex]\frac{0.5}{300} = \frac{3}{k} \implies k = \frac{3 \times 300}{0.5}[/tex]
or, k = 1800 cm = 18 m
Hence, the length of the actual submarine is 18 m.