Answer:
1. Identical to that of free fall
Explanation:
As we know that there is same external force acting on an object when it is released in the air which is given as
[tex]F = mg[/tex]
so here in vertical direction the acceleration is given as
[tex]a = \frac{F_y}{m}[/tex]
so we will have
[tex]a = \frac{mg}{m}[/tex]
[tex]a_y = g[/tex]
so we can say that in vertical direction the acceleration is always same while object is in vertical motion or it is in projectile motion
