Explanation:
Given that,
Number of turns in the coil, N = 52
Original are of the coil, [tex]A_1=0.275\ m^2[/tex]
It is stretched to have no area in 0.100 s, t = 0.1 s
The magnetic field strength, B = 1.2 T
To find,
The magnitude and the direction of average induced emf.
Solution,
The Faraday law gives the magnitude and the direction of induced EMF in the coil. Its formula is given by :
[tex]E=-\dfrac{Nd\phi}{dt}[/tex]
[tex]E=-\dfrac{Nd(BA)}{dt}[/tex]
[tex]E=-NB\dfrac{d(A)}{dt}[/tex]
[tex]E=-52\times 1.2\times \dfrac{(0-0.275)}{0.1}[/tex]
E = 171.6 volts
The direction of induced emf is given by Lenz law. It opposes the direction due to which it is produced. It is in counterclockwise direction.
