Answer:
35mA
Explanation:
Hello!
To solve this problem we must use the following steps
1. Find the electrical resistance of the metal rod using the following equation
[tex]R=\alpha \frac{l}{a}[/tex]
WHERE
α=
metal rod resistivity=2x10^-4 Ωm
l=leght=2m
A= Cross-sectional area
[tex]A=\frac{\pi }{4} d^2=\frac{\pi }{4} (0.06)^2=0.00283[/tex]
solving
[tex]R=(2x10^-4)\frac{2}{0.00283} =0.14[/tex]
2. Now we model the system as a circuit with parallel resistors, where we will call 1 the metal rod and 2 the man(see attached image)
3.we know that the sum of the currents in 1 and 2 must be equal to 5A, by the law of conservation of energy
I1+I2=5
4.as the voltage on both nodes is the same we can use ohm's law in resitance 1 and 2 (V=IR)
V1=V2
(0.14I1)=2000(i2)
solving for i1
I1=14285.7i2
5.Now we use the equation found in step 3
14285.7i2+i2=5
[tex]i2=\frac{5}{14285.7+1} =3.5x10^-4A=35mA[/tex]
