Answer:
255.61 m
Explanation:
Use [tex]s=ut +\frac{1}{2} at^{2}[/tex] in downwards direction from the moment of flight till the car hits the bottom.
As the car fly off the cliff the velocity of the car in vertical direction will be zero.
[tex]h =\frac{1}{2} 10(7.15)^{2}[/tex]
[tex]h=255.61 m[/tex]
