Answer : The maximum pressure that attained in the tank will be 55.3 atm
Explanation :
Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.
[tex]P\propto T[/tex]
or,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure = 36.0 atm
[tex]P_2[/tex] = final pressure = ?
[tex]T_1[/tex] = initial temperature = [tex]22.0^oC=273+22.0=295K[/tex]
[tex]T_2[/tex] = final temperature = [tex]180^oC=273+180=453K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{36.0atm}{295K}=\frac{P_2}{453K}[/tex]
[tex]P_2=55.3atm[/tex]
Thus, the maximum pressure that attained in the tank will be 55.3 atm
