Under some circumstances, a star can collapse into an extremely dense object made mostly of neutrons and called a neutron star. The density of a neutron star is roughly 1014 times as great as that of ordinary solid matter. Suppose we represent the star as a uniform, solid, rigid sphere, both before and after the collapse. The star's initial radius was 7.0×105km (comparable to our sun); its final radius is 15 km.

Respuesta :

Answer:

The question is incomplete however this kind of questions about determinate the angular speed and taking a reference of days rotating the first star.

w=0.11312 rad/s

Explanation:

The situation is about a two star the question is incomplete, miss the time rotate one star so we assume the first star rotated once in 30 days so:

Angular momentum

[tex]P_{m}=I*w[/tex]

The inertia

[tex]I=\frac{3}{5}*m*r^2[/tex]

The momentum must be conserved so

[tex]P_{m1}=P_{m2}[/tex]

[tex]I_{1}*w_{1}=I_{2}*w_{2}[/tex]

[tex]\frac{2}{5}*m*r_{1}^2*w_{1}=\frac{2}{5}*m*r_{2}^2*w_{2}[/tex]

notice don't have to know the mass or use the density however at the end can determinate

[tex]w_{2}=\frac{r_{1}*w_{1}}{r_{2}}[/tex]

Time can determinate the frequency so determinate angular speed of the first star

[tex]w_{1}=2\pi*f_{1}[/tex]

[tex]t_{1}=30days*\frac{24hr}{1day}*\frac{60minute}{1hr}*\frac{60s}{1minute}=2592000s[/tex]

[tex]f_{1}=\frac{1}{t_{1}}=\frac{1}{2592000}=3.858x10^-7Hz[/tex]

[tex]w_{1}=2.424x10^{-6}\frac{rad}{s}[/tex]

[tex]w_{2}=\frac{7.0x10^8m}{15x10^3m}*2592000[/tex]

[tex]w_{2}=0.11312 rad/s[/tex]