Answer:
62% and 161.29%
Step-by-step explanation:
Given that the percentage of adult height attained by girls who are x years old can be modeled by
[tex]f(x)=62+35log(x-4)[/tex], where
x represents the girl's age (from 5 to 15) and
f(x) represents the percentage of her adult height
A) When age =5, we have x=5
[tex]f(5) = 62+35log(5-4) = 62+35log 1\\= 62+0 =62[/tex]
So height when age is 5 is 62 %
B) The approximate of her adult height is
[tex]\frac{100}{62} \\=161.29%[/tex]