Answer:
The player's speed is 1.93 m/s.
Explanation:
Given that,
Mass of football = 71.5 kg
Speed = 2.00 m/s
Mass of football = 0.470 Kg
Speed = 12.5 m/s
We need to calculate the initial momentum of the football player and ball
[tex]P_{i}=(m+m_{b})v_{i}[/tex]
Put the value into the formula
[tex]P_{i}=(71.5+0.470)\times2.00[/tex]
[tex]P_{i}=143.94\ kg-m/s[/tex]
We need to calculate the final momentum of the system
[tex]P_{f}=mv+m_{b}v_{b}[/tex]
Put the value into the formula
[tex]P_{f}=71.5\times v+0.470\times12.5[/tex]
[tex]P_{f}=71.5\times v+5.875[/tex]
We need to calculate the relative to the ground
Using conservation of momentum
[tex]P_{i}=P_{f}[/tex]
Put the value into the formula
[tex]143.94=71.5\times v+5.875[/tex]
[tex]v=\dfrac{143.94-5.875}{71.5}[/tex]
[tex]v=1.93\ m/s[/tex]
Hence, The player's speed is 1.93 m/s.
