What is the concentration of ammonium ion in a 0.150 M solution of ammonia? The Kb value for ammonia is 1.80 x 10−5.

Respuesta :

[NH₄⁺] = 1.64 × 10⁻³ M

Explanation:

We have the following chemical equilibrium:

NH₃ + H₂O ⇔ NH₄⁺ + H O⁻

Kb is defined:

Kb = ( [NH₄⁺] × [H O⁻] ) / [NH₃]

and if we rearrange the therms:

Kb × [NH₃] = [NH₄⁺] × [H O⁻]

[NH₄⁺] × [H O⁻] = Kb × [NH₃]

The concentration of ammonium ion [NH₄⁺] is equal to the concentration of hydroxide ion [H O⁻]. Taking this in account we get:

[NH₄⁺]² = Kb × [NH₃]

[NH₄⁺]² = 1.80 × 10⁻⁵ × 0.150

[NH₄⁺] = √ (1.80 × 10⁻⁵ × 0.15)

[NH₄⁺] = 1.64 × 10⁻³ M

Learn more about:

problems with acid and bases

https://brainly.com/question/9758686

#learnwithBrainly