Answer:
163.02 kJ
Explanation:
Heat energy can be calculated using
Q=mcθ
where Q = Heat energy
m =mass
c = specific heat capacity
θ =temperature difference
here we need the specific heat capacity and the density of the soup.
Assumptions
- specific heat be approximate to specific heat of water =4.18 J/g C
- density = 1 g/cm3 (water)
- 1 ml = 1 cm3
- mass= volume * density
Q=mcθ
Q=(v*d)*cθ
Q = (500* 1) * 4.18 *(10-88)
Q = -163020 J
Q= 163.02 kJ
