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Find the solutions to y = (x – 1)2 for x = –3, 0, and 3.


(–3, –16), (0, 1), (3, 4)

(–3, 16), (0, 1), (3, 4)

(–3, –2), (0, 1), (3, 4)

(–3, –4), (0, –1), (3, 2)

Respuesta :

Funkeheart

Answer:

if the 2 is the power of (x-1) here is ur answer

[tex]y = (x - 1 ){}^{2} \\if \: x \: is \: \: equal \: to \: - 3 \\ y =( - 3 - 1) {}^{2} \\ y = ( - 4) {}^{2} \\ y = 16[/tex]

[tex]if \: x = 0 \\ y = (0 - 1) {}^{2} \\y = ( - 1) { }^{2} \\ y = 1[/tex]

[tex]if \: x = 3 \\ y = (3 - 1) {}^{2} \\ y = 2 { }^{2} \\ y = 4[/tex]

(-3,16) (0,1) (3,4)

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