Given a circle with measures of (C, d, and r) and a circle with measures of (C' ,d' , and r'). what is C' if d/d'=.25 and C=6?

Question

contestada

Respuesta :

WaywardDelaney WaywardDelaney · Answer 1 · 2019-11-13T16:29:02+01:00

Answer:

The value of c' is 24

Step-by-step explanation:

Given as for circle :

C = 6 And [tex]\frac{d}{d'}[/tex] = .25

For circle first

The Circumference of circle = C

Diameter of circle = d

Radius of circle = r

So , circumference of circle = 2 [tex]\pi[/tex] r

For circle second

The Circumference of circle = C'

Diameter of circle = d'

Radius of circle = r'

So , circumference of circle = 2 [tex]\pi[/tex] r'

Now, [tex]\frac{c}{c'}[/tex] = [tex]\frac{2 \pi r}{2 \pi r'}[/tex]

Or, ∵ Diameter = 2 × Radius

So, [tex]\frac{c}{c'}[/tex] = [tex]\frac{2 \pi d}{2 \pi d'}[/tex]

Or, [tex]\frac{6}{c'}[/tex] = [tex]\frac{2 \pi d}{2 \pi d'}[/tex]

So, [tex]\frac{6}{c'}[/tex] = [tex]\frac{25}{100}[/tex]

∴ c' = [tex]\frac{6\times 100}{25}[/tex] = 24

Hence The value of c' is 24 Answer