Answer:
5.77 m
Step-by-step explanation:
The swimming pool has a rectangle in the center of dimension 10 m by 8 m and two semicircles at each end.
So, the area of the floor of the pool will be
[tex](10 \times 8) + \frac{\pi (4)^{2} }{2} + \frac{\pi (4)^{2} }{2} =130.28[/tex] m²
Now, the perimeter of the pool is [tex]\frac{2 \times \pi \times (4) }{2} + \frac{2 \times \pi \times (4) }{2} + 2 \times 10 = 45.1428[/tex] m.
Now, it is given that the paved area around the pool is double the area of the pool.
If the width of the paved area is x m then
45.1428x = 2 × 130.28
⇒ x = 5.77 m (Answer)
