Answer:
The average velocity is 8 unit per sec
Explanation:
Given as :
The Distance x = 20 - 4t² unit
Change in time Δt = ( 2 - 0 ) s = 2 s
Let the velocity = V unit/s
∴ V = [tex]\frac{\partial (20 - 4t^{2})}{\partial x}[/tex]
Or, V = - 8t unit/s
Now velocity at t = 0
V1 = - 8 × 0 = 0 unit/s
And velocity at t = 2 sec
V2 = - 8 × 2 = - 16
So, Average velocity = [tex]\frac{v2 - v1}{2}[/tex] = [tex]\frac{- 16 - 0}{2}[/tex] = -8
Or, [tex]\begin{vmatrix}V\end{vmatrix}[/tex] = 8 unit/sec
Hence The average velocity is 8 unit per sec Answer
