The force of friction is 213.2 N
Explanation:
The frictional force acting on an object sliding on a surface is given by:
[tex]F_f = \mu mg[/tex]
where:
[tex]\mu[/tex] is the coefficient of friction
m is the mass of the object
g is the acceleration of gravity
In this problem we have
[tex]\mu=0.750[/tex]
m = 29 kg
[tex]g=9.8 m/s^2[/tex]
Therefore, the force of friction is
[tex]F_f = (0.750)(29)(9.8)=213.2 N[/tex]
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