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Brian irons \dfrac29 9 2 ​ start fraction, 2, divided by, 9, end fraction of his shirt in 3\dfrac353 5 3 ​ 3, start fraction, 3, divided by, 5, end fraction minutes. Brian irons at a constant rate. At this rate, how much of his shirt does he iron each minute?

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luisejr77

Answer: He irons [tex]\frac{5}{81}[/tex] of his shirt each minute.

Step-by-step explanation:

The complete exercise is: "Brian irons [tex]\frac{2}{9}[/tex] of his shirt in [tex]3\frac{3}{5}[/tex] minutes. Brian irons at a constant rate. At this rate, how much of his shirt does he iron each minute?"

Let be "x" represents how much of his shirt  Brian iron each minute.

Convert the mixed number to an improper fraction. Multiply the whole number part by the denominator of the fraction and add the product to the numerator. The denominator does not change. Then:

[tex]3\frac{3}{5}=\frac{(3*5)+3}{5}=\frac{18}{5}[/tex]

Set up the following proportion:

[tex]\frac{\frac{2}{9}}{\frac{18}{5}}=\frac{x}{1}[/tex]

Finally, solving for "x", you get:

[tex](\frac{5}{81})(1)=x\\\\x=\frac{5}{81}[/tex]

Therefore, he irons [tex]\frac{5}{81}[/tex] of his shirt each minute.

The answer is 5/81 Khan Academy

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