Respuesta :
[tex]\text{Turn the question into equations to find your answer}\\\\\text{Consultant A:}\\\\y=75x+160\\\\\text{Consultant B:}\\\\y=90x\\\\\text{Consultant C:}\\\\y=80x+140\\\\\text{Plug in 4 to x for consultant a and c because a variable already represents}\\\text{an hour}\\\\y=75(4)+160\\\\y=80(4)+140\\\\y=90(5)\\\\\text{Solve:}\\\\y=75(4)+160\\\\y=460\\\\y=80(4)+140\\\\y=460\\\\y=90(5)\\\\y=450\\\\\text{This means that Consultant C offers a cheaper price of \$450}[/tex]
Answer:
B. Consultant B
Step-by-step explanation:
The question asked us to determine the price each consultant charges for a period of 5 hours and then get the cheapest among them.
Let the total charges for 5 hours session = a
Consultant A
He charges $160 for the first hour and $75 after the first. That means the remaining 4 hours he charges 75 × 4 = $300.
a = 160 + 300 = $460
Consultant B
He charges $90 per hour. This means his charge for 5 hours session is 5 × 90 = $450
a = 90 × 5 = $450
Consultant C
He charges $140 for the first hour and $80 after the first hour. The remaining 4 hours session he will charge 4 × 80 = $320.
a = 140 + 320 = $460
Consultant B offers the cheapest price of $450